MatrixSolutions

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The general idea of a matrix inverse is that if A is a matrix, its inverse, \mathbf{X}^{-1} is the matrix which, when multiplied by A yields the identity matrix, I. I, in turn, is the matrix which, when multiplied by any matrix B just gives back B.

For the problem posed in the quiz:

find

\mathbf{X}=\left[\begin{array}{cc} 1 & 4\\ -1 & 2\end{array}\right]^{-1}

I think that the easiest solution is to solve as a set of simultaneous equations. If \mathbf{X} = \left[\begin{array}{cc} a & b\\ c & d\end{array}\right],

\left[\begin{array}{cc} 1 & 4\\ -1 & 2\end{array}\right] \left[\begin{array}{cc} a & b\\ c & d\end{array}\right] = \left[\begin{array}{cc} 1 & 0\\ 0 & 1\end{array}\right]

Thus, the rules of matrix multiplication give us this set of four equations:

a + 4c = 1
b + 4d = 0
a + 2c = 0
b + 2d = 1

which is very easy to solve by substitution:

b = − 4d
a = 2c
2c + 4c = 1
c = 1 / 6
etc,...

Of course, you can use Cramer's rule if you remember it, or some other solving algorithm. I think you can get a matrix solution app for your iPhone, as well.

We will use this general concept a lot in Principles of Neuroimaging. In particular, when we imagine the image result of an experiment to be the sum of a variety of influences (experimental and otherwise), we will use matrix form to evaluate the strength of each of these influences in creating our experimental result.